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The length of the second's pendulum on the surface of the earth is 1 m . If the acceleration due to gravity on the surface of the moon is one-sixth of the acceleration due to gravity of the earth, then the length of the second's pendulum on the surface of the moon will be

Options

  1. A1 6 m
  2. B6 m
  3. C1 36 m
  4. D36 m

Correct answer

A. 1 6 m

Step-by-step solution

Seconds pendulum is a special pendulum having a time period of 2 s . Using the formula T = 2 π L g If the time period remains the same and g is reduced by a factor of 6 . L should be reduced by a factor of 6. ⇒ L = 1 6 m on moon.

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