Consider a pair of identical pendulums, which oscillate with equal amplitude independently such that when one pendulum is at its extreme position making an angle of 2 o to the right with the vertical, the other pendulum makes an angle of 1 o to the left of the vertical. What is the phase difference (in degree) between the pendulums?

Step-by-step solution

Assuming the two pendulums follow the following functions of their displacement : θ 1 = θ 0 sin (ωt + ϕ 1 ) ..(i) and θ 2 = θ 0 sin (ωt + ϕ 2 ) ..(ii) As it is given that amplitude and time period being equal but phases being different. Now, for first pendulum at any time t θ 1 = θ 0 (Right extreme) From Eq. (i), we get ⇒ θ 0 = θ 0 sin (ωt + ϕ 1 ) or 1 = sin (ωt + ϕ 1 ) or ω t + ϕ 1 = π 2 &hellip