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The length of a simple pendulum executing simple harmonic motion is increased by 21 % . The percentage increase in the time period of the pendulum of increased length is

Options

  1. A11 %
  2. B21 %
  3. C42 %
  4. D10 %

Correct answer

D. 10 %

Step-by-step solution

Let the lengths of the pendulum be ( 100 l ) and ( 121 l ) Since we know the time period of a simple pendulum is given by T = 2 π l g ∴ T ' T = 121 100 = 11 10 ∴ Fractional change = T ' - T T = 11 - 10 10 = 1 10 ∴ Percentage change = 10 %

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