NTA Abhyas JEE Main2020PhysicsOscillationsPractice
A particle performs SHM with an amplitude of 5 m . If at x = 4 m , the magnitude of velocity and acceleration are equal, then the time period of SHM (in seconds) is
Options
- A2 π 3
- B4 π 3
- C8 π 3
- D6 π 3
Correct answer
C. 8 π 3
Step-by-step solution
v = ω 5 2 - 4 2 = 3 ω a = ω 2 × 4 a = v 4 ω 2 = 3 ω ω = 3 4 = 2 π T T = 8 π 3   s