NTA Abhyas JEE Main2020PhysicsOscillationsPractice
One end of a spring of force constant K is fixed to a vertical wall and other to a body of mass m resting on smooth horizontal surface. There is another wall at a distance of 3 x 0 from the body. If all the collisions are elastic and spring is compressed by 2 x 0 and released, then the time period of oscillation is
Options
- A5 π 3 m K
- B5 π 4 m K
- C3 π 2 m K
- D4 π 3 m K
Correct answer
A. 5 π 3 m K
Step-by-step solution
T = 2 π m k t = T 2 + 2 × T 6 = 5 T 6