NTA Abhyas JEE Main2020PhysicsOscillationsPractice
The equation of the resultant motion of the number of simple harmonic motions is E c ( 1 + K sin ω 2 t ) sin ω 1 t . The number of simple harmonic components is/are
Options
- A1
- B2
- C3
- D4
Correct answer
C. 3
Step-by-step solution
Y = E c ( 1 + K sin ω 2 t ) sin ω 1 t Y = E c sin ω 2 t + E c k sin ω 2 sin ω 1 t Y = E c sin ω 1 t + E c K 2 cos ω 2 + ω 1 t E c K 2 ω 2 - ω 1 t Thus there are three simple harmonic waves of frequency ω 1 , ω 1 + ω 2 and ω 1 - ω 2