NTA Abhyas JEE Main2020PhysicsOscillationsPractice
The system shown in the adjacent figure is in equilibrium. The mass of the container with liquid is M , the density of the liquid in the container is ρ and volume of the block is V . If the container is now displaced downwards through a distance x 0 and released such that block remains well inside the liquid, during subsequent motion (ignore viscosity)
Options
- ATime period of SHM of the container will be 2 π M +2 ρ v k
- BTime period of SHM of the container will be 2 π M + ρ v k
- CThe amplitude of SHM of the container will be x 0 2
- DContainer will not perform SHM
Correct answer
B. Time period of SHM of the container will be 2 π M + ρ v k
Step-by-step solution
M g - k x + Δ x + ρ V g - a = M a Where M g + ρ V g = K Δ x ⇒ M + ρ V a = - K x Or a - k x M + ρ V or ω = - k M + ρ V ⇒ T = 2 π M + ρ V K The amplitude of SHM will be x 0