NTA Abhyas JEE Main2020PhysicsOscillationsPractice
A particle starts SHM from the mean position. Its amplitude is a and total energy E . At one instant its kinetic energy is 3 E 4 . Its displacement at that instant is
Options
- Aa 2
- Ba 2
- Ca 3 2
- Da 3
Correct answer
B. a 2
Step-by-step solution
K = 1 2 m ω 2 ( a 2 - y 2 ) 3 4 E = 1 2 m ω 2 ( a 2 - y 2 ) 3 4 1 2 m ω 2 a 2 = 1 2 m ω 2 ( a 2 - y 2 ) y 2 = a 2 - 3 4 a 2 = a 2 4 ⇒ y = a 2