The position and velocity of a particle executing simple harmonic motion at t = 0 are given by 3 cm and 8 cm s - 1 respectively. If the angular frequency of the particle is 2 rad s - 1 , then the amplitude of oscillation (in cm ) is

Step-by-step solution

Given, the position and velocity of the particle executing SHM . y = 3   cm v = 8   cm   s - 1 Angular frequency, ω = 2   rad   s - 1 The velocity, v = ω a 2 - y 2 8 = 2 a 2 - 3 2 4 = a 2 - 3 2 16 = a 2 - 9 a 2 = 25 a = 5   cm