NTA Abhyas JEE Main2020PhysicsOscillationsPractice
The instantaneous displacement of a simple harmonic oscillator is given by y = a cos ω t + π 4 . Its speed will be maximum at the time
Options
- A2 π ω
- Bω 2 π
- Cω π
- Dπ 4 ω
Correct answer
D. π 4 ω
Step-by-step solution
Speed is maximum when y = 0 ∴ 0 = a cos ω t + π 4 ω t + π 4 = ( 2 n + 1 ) π 2 ω t = n π + π 4 t = n π ω + π 4 ω for n = 0, t = π 4 ω