Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas JEE Main2020PhysicsOscillationsPractice

What will be the displacement equation of the simple harmonic motion obtained by combining the motions? x 1 = 2 sin ⁡ ω t , x 2 = 4 sin ⁡ ω t + π 6 a n d x 3 = 6 sin ⁡ ω t + π 3

Options

  1. Ax = 10.25 sin ⁡ ω t + ϕ
  2. Bx = 10.25 sin ⁡ ω t - ϕ
  3. Cx = 11.25 sin ⁡ ω t + ϕ
  4. Dx = 11.25 sin ⁡ ω t - ϕ

Correct answer

C. x = 11.25 sin ⁡ ω t + ϕ

Step-by-step solution

The resultant equation is x = A sin ⁡ ω t + ϕ ∑ A x = 2 + 4 cos ⁡ 30 ° + 6 cos ⁡ 60 ° = 8.46 And ∑ A y = 4 sin ⁡ 30 ° + 6 cos ⁡ 30 ° = 7.2 ∴       A = ∑ A x 2 + ∑ A y 2 =     8.46 2 + 7.2 2 = 11.25 And tan ⁡ ϕ = ∑ A y ∑ A x = 7.2 8.46 = 0.85 ⇒     ϕ = tan - 1 ⁡ 0.85 = 40.4 ° Thus, the displacement equation of combined motion is x = 11.25 sin &#8289

Practice Oscillations on Quantrex Academy →

More from Oscillations

A tank contains two immiscible liquids of densities 6 and 2 . The higher density liquid is filled up to a height L/2 from the bottom. A thin rod of density and length L is fully im 2026The frequency of oscillation of a mass m suspended by a spring is v₁ . If the length of the spring is cut to half, the same mass oscillates with frequency v₂ . The value of v₂/v₁ i 2026A spring stretches by 2 mm when it is loaded with a mass of 200 g. From equilibrium position the mass is further pulled down by 2 mm and released. The frequency associated with the 2026A particle is executing simple harmonic motion. Its amplitude is A and time period is 5 sec. The time required by it to move from x = A to x = A 2 is _______ sec. 2026Match List-I with List-II. List-I List-II A. ^2 t I. Periodic with time period T = but not simple harmonic motion (SHM) B. ^3(2 t) II. Periodic with time period T = 2 but Not SHM C 2026A uniform disc of radius R and mass M is free to oscillate about the axis A as shown in the figure. For small oscillations the time period is ______. ( g is acceleration due to gra 2026The velocity of a particle executing simple harmonic motion along x -axis is described as v^2 = 50 - x^2 , where x represents displacement. If the time period of motion is x 7 s, t 2026The equation of motion of a particle is given by x = a (50t + 3 ) cm. The particle will come to rest at time t₁ and it will have zero acceleration at time t₂ . The t₁ and t₂ respec 2026 Full Oscillations list All NTA Abhyas JEE Main PYQs