NTA Abhyas JEE Main2020PhysicsOscillationsPractice
The x - t graph of a particle undergoing simple harmonic motion is shown below. The acceleration of the particle at t = 4 3 s is:
Options
- A3 32 π 2 c m   s - 2
- B- π 2 32 c m   s - 2
- Cπ 2 32 c m   s - 2
- D- 3 32 π 2 c m   s - 2
Correct answer
D. - 3 32 π 2 c m   s - 2
Step-by-step solution
x = sin ⁡ 2 π 8 t a = - ω 2 x = - 2 π 8 × 2 π 8 × sin ⁡ 2 π 8 × 4 3 ⇒ a = π 2 16 × 3 2 = - 3 π 2 32 cm   s - 2