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The time-period of a simple pendulum of length 5 m suspended in a car moving with uniform acceleration of 5 m s - 2 in a horizontal straight road is g = 10 m s - 2

Options

  1. A2 π 5 s
  2. Bπ 5 s
  3. C5 π s
  4. D4 π s

Correct answer

A. 2 π 5 s

Step-by-step solution

Given, Length of simple pendulum, l = 5 m Acceleration of car a = 5 m s - 2 Now g e f f e c t i v e = a 2 + g 2 = 5 2 + 10 2 = 125 = 5 5 T = 2 π l g e f f e c t i v e T = 2 π 5 5 5 T = 2 π 5 s

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