NTA Abhyas JEE Main2020PhysicsOscillationsPractice
A particle executing SHM has a maximum speed of 0.5 m s - 1 and a maximum acceleration of 1.0 m s - 2 . The angular frequency of oscillation is
Options
- A2   rad   s - 1
- B0.5 rad s - 1
- C2 π   rad   s - 1
- D0 .5 π   rad   s - 1
Correct answer
A. 2   rad   s - 1
Step-by-step solution
In SHM, Maximum velocity v m a x = ω A Maximum acceleration a m a x = A ω 2 ⇒     ω = A ω 2 A ω = a m a x v m a x v m a x = 0.5   m   s - 1 a m a x = 1.0   m   s - 1 ω = 1 0.5 = 10 5  = 2   rad   s - 1