A particle of mass m is performing the linear simple harmonic motion. Its equilibrium is at x = 0 , force constant is K and amplitude of SHM is A. The maximum power supplied by the restoring force to the particle during SHM will be:

Step-by-step solution

Power supplied by the restoring force F = K x is: P = F V P = K x w A 2 - x 2 P = K K m A 2 x 2 - x 4 P will be max when d p d x = 0 ⇒ A 2 2 x - 4 x 3 = 0 x = A 2 P m a x = P | a t x = A 2 = K K m A 2 A 2 2 - A 2 4 P m a x = K 3 2 A 2 2 m