NTA Abhyas JEE Main2020PhysicsOscillationsPractice
The amplitude of a simple pendulum is 10cm. When the pendulum is at a displacement of 4cm from the mean position, then what is the ratio of kinetic and potential energies at that point?
Correct answer
5.25
Step-by-step solution
K . E P . E = 1 2 m w 2 A 2 - x 2 1 2 m w 2 x 2 K . E P . E = A 2 - x 2 x 2 = 10 2 - 4 2 4 2 = 84 16 K . E P . E = 21 4 = 5.25