Ethylene glycol is used as antifreeze to reduce freezing point of water to -2.4^ C . What mass of antifreeze is required for 2 ~L water? (K_f. water .=1.86 ~K ~kg / mole)

Correct answer: B. 160 ~g aligned w_ solute & = Δ T_f × w_ water × M_ solute K_f & =(2.4 × 2 × 0.062)/(1.86)=160 g aligned [Mass of 2 L of water is 2 kg .]

AIIMS 201827 May

Exam: AIIMS
Year: 2018
Date: 27 May
Subject: Chemistry
Chapter: Solutions

AIIMS 2018 · 27 May · Chemistry · Solutions

Ethylene glycol is used as antifreeze to reduce freezing point of...

Ethylene glycol is used as antifreeze to reduce freezing point of water to

-2.4^{\circ} \mathrm{C}

. What mass of antifreeze is required for

2 \mathrm{~L}

water? \left(K_f\right.

water \left.=1.86 \mathrm{~K} \mathrm{~kg} / \mathrm{mole}\right)

Options

A $16 \mathrm{~kg}$
B $160 \mathrm{~g}$
C $1.60 \mathrm{~kg}$
D $16 \mathrm{~g}$

Correct answer

B. $160 \mathrm{~g}$

Step-by-step solution

\begin{aligned} w_{\text{solute }} & =\frac{\Delta T_f \times w_{\text{water }} \times M_{\text{solute }}}{K_f} \\ & =\frac{2.4 \times 2 \times 0.062}{1.86}=160 \mathrm{ g}\end{aligned}

[Mass of

2 \mathrm{ L} of water is

\mathrm{ kg}

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