The following reaction R − CH 2 CH 2 N + (CH 3 ) 3 OH − → Δ RCH = CH 2 +N(CH 3 ) 3 + H 2 O is called

Step-by-step solution

Trialkyl ammonium hydroxide undergoes Hoffmann elimination to give less substituted alkene. Elimination of more acidic β -H occurs from that β -carbon, which is joined to largest number of hydrogens. Thus, elimination of H occurs opposite to that of Saytzeff rules.