NTA Abhyas NEET2020ChemistryCarboxylic Acid DerivativesPractice
In the given reaction sequence C 6 H 5 − COOH → SOCl 2 ( A ) → NH 2 OH ( B ) → NaOH / Δ ( C ) , 'C' will be
Options
- AC 6 H 5 C O C l
- BC 6 H 5 - C | | O - N H O H
- CC 6 H 5 - N H 2
- DC 6 H 5 - N = C = O
Correct answer
C. C 6 H 5 - N H 2
Step-by-step solution
Here the final product C is aniline and the reaction is as follows C 6 H 5 - C O O H → S O C l 2 C 6 H 5 - C | | O - C l ( A ) → N H 2 O H C 6 H 5 - C | | O - N H O H ( B ) → N a O H [ C 6 H 5 - N = C = O ] → C 6 H 5 - N H 2