Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas NEET2020ChemistryClassification of Elements and Periodicity in PropertiesPractice

N 0 /4 atoms of X(g) are converted into X + (g) by energy E 1 . N 0 /4 atoms of X(g) are converted into X – (g) by energy E 2 . Hence, ionisation potential and electron affinity of X(g) are :

Options

  1. A4 E 1 N 0 , 4 E 1 - E 2 N 0
  2. B4 E 1 N 0 , 4 E 2 N 0
  3. CE 1 - E 2 N 0 , 4 E 2 N 0
  4. DNone is correct

Correct answer

B. 4 E 1 N 0 , 4 E 2 N 0

Step-by-step solution

X g ⟶ X + g + e - If I ionisationh energy then ∴ N 0 4 I = E 1 ∴ I = 4 E 1 N 0 If E is electron-affinity then X g + e - ⟶ X - g N 0 4 E = E 2 ∴ E = 4 E 2 N 0

Practice Classification of Elements and Periodicity in Properties on Quantrex Academy →

More from Classification of Elements and Periodicity in Properties

Match the following List I List II A. Technetium I. Non-metal B. Fluorine II. Transition metal C. Tellurium III. Lanthanoid D. Dysprosium IV. Metalloid 2026Which of the following properties increases from fluorine to iodine in group? 2026Identify the metalloid element from the following. 2026Which among the following elements does NOT exhibit -2 oxidation state? 2026Which has the maximum electropositive character? 2026The hydride with lowest acid strength among the following is 2026Among the following options, the correct trend in the electron gain enthalpy is 2026Given below are two statements : One is labelled as Assertion A and the other is labelled as Reason R . Assertion A : The first ionization enthalpy of O is lower than that of N and 2026 Full Classification of Elements and Periodicity in Properties list All NTA Abhyas NEET PYQs