NTA Abhyas NEET2020ChemistryClassification of Elements and Periodicity in PropertiesPractice
In a compound AB, electro negativity difference between A and B is 1.9 . Atomic radius A and B are 4 A ° and 2 A ° . The distance between A and B atoms means d A − B is
Options
- A6.72 A °
- B5.82 A °
- C6.9 A °
- D7.5 A °
Correct answer
B. 5.82 A °
Step-by-step solution
d A − B = r A + r B − 0.09 ( x A − x B ) = 6 − 0.09 ( 1.9 ) ≈ 5.829