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NTA Abhyas NEET2020ChemistryClassification of Elements and Periodicity in PropertiesPractice

The Energy needed For Li g → Li 3+ g + 3 e − is 19600 kJ mole -1 . Li g = 520 kJmole − 1 . Calculate IE 2 For Li g . ionisation energy of H = 13.6 eV

Options

  1. A75.3 eV/species
  2. B25.30 eV/species
  3. C30.45 eV/species
  4. D62.40 eV/species

Correct answer

A. 75.3 eV/species

Step-by-step solution

Li (g) → Li + 3 + 3 e -  ;     IP I + IP II + IP III = 203 · 1   ev/species Li → Li + (g) + 1 e - ;       5 · 4 eV / species  IP I Li + (g) → Li 2+ + 1 e - ;       IP II = ??  Li + 2 → Li + 3   (g);      IP III = IE Li 2+ = 1 3 · 6 × 3 2  =  122.4 eV/species

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