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NTA Abhyas NEET2020ChemistryIonic EquilibriumPractice

Determine the solubility of silver chromate at 298 K given its K sp value is 1.1 × 10 -12 .

Options

  1. A6.5 × 10 -5
  2. B2.4 × 10 -2
  3. C3.6 × 10 -3
  4. D8.9 × 10 -4

Correct answer

A. 6.5 × 10 -5

Step-by-step solution

Ag 2 CrO 4 ⇌ 2Ag + + CrO 4 2 - ; K sp = 1.1 × 10 - 12 S 2S S K sp = Ag + 2 · CrO 4 2 - K sp = [2S] 2 · [S] = 4S 3 S 3 = K sp 4 = 1.1 × 10 - 12 4 ⟹ S = 6.53 × 10 - 5

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