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NTA Abhyas NEET2020ChemistryIonic EquilibriumPractice

A 0.01 M ammonia solution is 5 % ionised, its pH will be

Options

  1. A11.80
  2. B10.69
  3. C7.22
  4. D12.24

Correct answer

B. 10.69

Step-by-step solution

Given, aqueous solution of N H 3 weak base C = 0.01 M α = 5 % = 5 100 O H - = C α = 0.01 × 5 100 = 5 × 10 - 4 p O H = - log ⁡ [ O H - ] = log ⁡ 5 × 10 - 4 = 4 log ⁡ 10 - log ⁡ 5 = 4 - 0.6989 = 3.3010 ∴ p H = 14 - p O H = 14 - 3.3010 = 10.6990

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