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NTA Abhyas NEET2020ChemistryIonic EquilibriumPractice

The equilibrium constant for the given reaction is approximately 10 – 3 HPO 4 2 − aq + HCO 3 − aq ⇌ H 2 PO 4 − aq + CO 3 2 − aq Which is strongest conjugate base in the given reaction?

Options

  1. AH P O 4 2 - a q
  2. BH C O 3 - a q
  3. CH 2 P O 4 - a q
  4. DC O 3 2 - a q

Correct answer

D. C O 3 2 - a q

Step-by-step solution

CO 3 2 − +  H 2 PO 4 − ⇌ HPO 4 2 −   +  HCO 3 2 −   Kc = 10 3 Since the value of K c for this reaction is greater than 1, it means this reaction is favourable in forward direction. Therefore, C O 3 2 - is the stronger conjugate base than H P O 4 2 -

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