NTA Abhyas NEET2020ChemistryIonic EquilibriumPractice
An acid solution of 0.005 M has a pH of 5. The degree of ionisation of acid is
Options
- A0.1 × 10 - 2
- B0.2 × 10 - 2
- C0.5 × 10 - 4
- D0.6 × 10 - 6
Correct answer
B. 0.2 × 10 - 2
Step-by-step solution
Acid, [ H + ] = 10 - p H = 10 - 5 α = H + C o n c e n t r a t i o n = 10 - 5 0.005 = 0.2 × 10 - 2