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Solubility product K s p of saturated P b C l 2 in water is 1.8 × 10 - 4 m o l 3 d m - 9 . What is the concentration of P b 2 + in the solution?

Options

  1. A0.45 × 10 - 4 1 3 m o l d m - 3
  2. B1.8 × 10 - 4 1 3 m o l d m - 3
  3. C0.9 × 10 - 4 1 3 m o l d m - 3
  4. D2.0 × 10 - 4 1 3 m o l d m - 3

Correct answer

A. 0.45 × 10 - 4 1 3 m o l d m - 3

Step-by-step solution

For the reaction of the A B 2 i.e. P b C l 2 K s p = 4 s 3 Or, S = K s p 4 1 3 Given, K s p = 1.8 × 10 - 4 m o l 3 d m - 9 ∴ Solubility of P b + 2 ions will be ∴ S = 1.8 × 10 - 4 4 1 3 = 0.45 × 10 - 4 1 3 m o l . d m - 3

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