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In a saturated solution of the sparingly soluble strong electrolyte AgIO 3 ( molecular mass = 283 ) the equilibrium which sets in is AgIO 3 s ⇌ Ag + aq + IO 3 − aq If the solubility product constant K sp of AgIO 3 at a given temperature is 1 · 0 × 1 0 - 8 , what is the mass of AgIO 3 contained in 100 ml of its saturated solution ?

Options

  1. A1 · 0 × 1 0 - 4 g
  2. B2 8 · 3 × 1 0 - 2 g
  3. C1 · 0 × 1 0 - 7 g
  4. D2 · 8 3 × 1 0 - 3 g

Correct answer

D. 2 · 8 3 × 1 0 - 3 g

Step-by-step solution

AgIO 3 ⇌ Ag + + IO 3 - [ S = Solubility ] S S K sp = S 2 Or, S 2 = 1 · 0 × 1 0 - 8 S = 1 · 0 × 1 0 - 4 mol / it = 1 · 0 × 1 0 - 4 × 2 8 3 g / lit = 2 8 · 3 × 1 0 - 4 gm / 100 ml = 2 · 8 3 × 1 0 - 3 gm / 100 ml

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