4   ml of H C l solution of p H = 2 is mixed with 6 m l of N a O H solution of p H = 12 . What would be the final p H of solution? l o g 2 = 0.3

Step-by-step solution

[ H C l ] = 0.01 [ N a O H ] = 0.01 M m i x t = 6 × 0.01 - 4 × 0.01 10 = 0.02 10 [ O Θ H ] = 0.002 pOH = − log ( 0.002 ) = 2.7