What mass of AgI will dissolve in 0.1 L of 1.0 M NH 3 ? Neglect change in conc. of NH 3 . (Atomtextc weight of Ag & I are 108 amu and 127 amu respectively) Given : K sp AgI = 1.5 × 1 0 - 1 6 ( m o l / L ) 2 ; K f Ag NH 3 2 + = 1.6 × 1 0 7 .

Step-by-step solution

Due to higher value of K f , mostly Ag + converted into complex. AgI s ⇌ Ag + aq. + I - aq. ; K sp Ag + aq. + 2 NH 3 aq. ⇌ Ag NH 3 2 + aq. ; K f ______________________________________ overal reaction is AgI s + 2 NH 3 aq. ⇌ Ag NH 3 2 + aq. + I - aq. K eq = K sp · K f K sp · K f = x 2 1 2 ∴ x = 4.9 × 1 0 - 5 mol/litre So, mass of AgI required is = 4.9 × 1 0 - 5 × 2 3 5 = 0.0115 g/L I n 0.1 L , m a s s o f A g I d i s s o l v e d w i l l b e = 0.0115 10 g = 1.15 ×10 - 3 g