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NTA Abhyas NEET2020ChemistryIonic EquilibriumPractice

Two solutions, A and B, each of 100 L was made by dissolving 4 g of NaOH and 9.8 g of H 2 S O 4 in water, respectively. The pH of the resultant solution obtained from mixing 40 L of solution A and 10 L of solution B is

Options

  1. A5.3
  2. B10.6
  3. C9.4
  4. D7.5

Correct answer

B. 10.6

Step-by-step solution

M ( H 2 S O 4 ) = 9.8 98 × 100 = 1 0 - 3 m M N a O H = 4 40 × 100 = 1 0 - 3 m Equivalents of resulting solution [ O H – ] = 40 × 1 0 - 3 - 10 × 1 0 - 3 × 2 50 = 2 5 × 1 0 - 3 pOH = 3 . 39 , pH = 10.6

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