The pH of a solution prepared by mixing 2.0 ml of HCl solution of pH 3.0 and 3.0 ml of NaOH of pH 10.0 is

Step-by-step solution

Given, for HCl, p H = 3 [ H + ] = 1 0 - 3 = M 1 V 1 = 2 m l For NaOH, p H = 10 , [ H + ] = 1 0 - 10 = M 2 V 2 = 3 m l M 1 V 1 - M 2 V 2 = M R ( V 1 + V 2 ) 1 0 - 3 × 2 - 1 0 - 10 × 3 = M R ( 2 + 3 ) 2 × 1 0 - 3 = 5 × M R M R = 4 × 1 0 - 4 = [ H + ] p H = l o g ( 4 × 1 0 - 4 ) = 4 - 0.6020 = 3.39 ≈ 3.5