Calculate the pH of a solution obtained by mixing 50 ml of 0.01 M B a ( O H ) 2 solution with 50 ml water.

Step-by-step solution

N 1 V 1 B a ( O H ) 2 = N 2 V 2 m i x t u r e [Normality of solution of B a ( O H ) 2 = 2 × molarity, as its mol. wt = 2 x eq. wt as n- factor is 2 for it. ] 0.01 × 2 × 50 = N 2 × ( 50 + 50 ) (as it is assumed as 100% ionised). N 2 = 0.01 × 100 100 = 0.01 N p O H = - l o g [ O H - ] = - l o g 1 0 - 2 = 2 l o g 10 p O H = 2 p H + p O H = 14 p H + 2 = 14 p H = 12