NTA Abhyas NEET2020ChemistryIonic EquilibriumPractice
The p H value of decinormal solution of N H 4 O H , which is 20 % ionized, is -
Options
- A13.30
- B14.70
- C12.30
- D12.95
Correct answer
C. 12.30
Step-by-step solution
OH − = 0.1 × 20 100 O H – = 0.1 × 0.2 = 2 × 10 –2 pOH= -log[OH - ] = 2- log2 p O H = 1.7 , p H = 14 – p O H = 14 - 1.7 = 12.3