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NTA Abhyas NEET2020ChemistryIonic EquilibriumPractice

The equilibrium constant for the reaction given is 3.6 × 1 0 - 7 OCl − aq + H 2 O l ⇌ HOCl aq + OH − aq . What is Ka for HOCl?

Options

  1. A2.77 × 1 0 - 8
  2. B3.6 × 1 0 - 7
  3. C6 × 1 0 - 4
  4. D2.8 × 1 0 - 6

Correct answer

A. 2.77 × 1 0 - 8

Step-by-step solution

K e q = K w K a 3.6 × 1 0 - 7 = K w K a K a = 1 0 - 14 3.6 × 1 0 - 7 = 2.77 × 1 0 - 8

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