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NTA Abhyas NEET2020ChemistryIonic EquilibriumPractice

The [H + ] of a resulting solution that is 0.01 M acetic acid (K a = 1.8 x 10 -5 ) and 0.01 M in benzoic acid (K a = 6.3 x 10 -5 ) is

Options

  1. A9 x 10 -4
  2. B81 x 10 -4
  3. C9 x 10 -5
  4. D2.8 x 10 -3

Correct answer

A. 9 x 10 -4

Step-by-step solution

H + = k 1 C 1 + k 2 C 2 (for mixture of two weak acids) = 1.8 × 1 0 - 5 × 0.01 + 6.3 × 1 0 - 5 × 0.01 = 18 × 1 0 - 8 + 6 3 × 1 0 - 8 = 9 × 1 0 - 4

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