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NTA Abhyas NEET2020ChemistryIonic EquilibriumPractice

The first and second dissociation constants of an acid H 2 A a r e 1.0 × 10 - 5 a n d 5.0 × 10 - 10 respectively. The overall dissociation constant of the acid will be

Options

  1. A5.0 × 10 - 5
  2. B5.0 × 10 15
  3. C5.0 × 10 - 15
  4. D0.2 × 10 5

Correct answer

C. 5.0 × 10 - 15

Step-by-step solution

Given K 1 = 1.0 × 10 − 5 , K 2 = 1.0 × 10 − 5 so overall dissociation constant of the acid will be K = K 1 × K 2 = 1.8 × 10 - 5 × 5.0 × 10 - 10 = 10 × 10 - 15

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