Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas NEET2020ChemistryIonic EquilibriumPractice

100 mL of a solution with pH = 6 is diluted to 1000 mL by adding water. pH will

Options

  1. Adecrease by 0.7 unit
  2. Bincrease by 1 unit
  3. Cincrease by 9 units
  4. Dincrease by 0.7 unit

Correct answer

D. increase by 0.7 unit

Step-by-step solution

pH = 6 [ H + ] = 1 0 - 6 M 100 × 1 0 - 6 = M × 1000 or M = 1 0 - 7 [ H + ] already present in water = 1 0 - 7 Total [ H + ] = 1 0 - 7 + 1 0 - 7 = 2 × 1 0 - 7 p H = - l o g 2 × 1 0 - 7 = 7 - l o g 2 p H = 7 - 0.3010 = 6.7

Practice Ionic Equilibrium on Quantrex Academy →

More from Ionic Equilibrium

What amount of NaOH should be dissolved in a 500 mL solution, so that the p ^ H of solution is 12 at 298 K ? 2026Which of the following buffer solutions is used for precipitation of cations of the III A group? 2026The degree of dissociation of weak acid is directly proportional to 2026Which from the following is Lewis base? 2026The solubility of Fe(OH) ₃ is x mole per liter. Find its K_ sp . 2026The Basic buffer solution is made with 0.1 M NH ₄ OH and 0.2 M NH ₄ Cl . If K_b for the base is 1.8 10⁻⁵ , what is the pH of the buffer? 2026The hydrogen ion concentration of the ocean is about 2 10⁻⁹ M . What is the pOH of ocean? 2026Calculate the dissociation constant of a weak monobasic acid if it is 0.04% dissociated in a 0.01M solution. 2026 Full Ionic Equilibrium list All NTA Abhyas NEET PYQs