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NTA Abhyas NEET2020ChemistryIonic EquilibriumPractice

The dissociation constant of a weak monoprotic acid, which is 0.01 % ionised in 1.00 M solution, is

Options

  1. A1 × 1 0 - 8
  2. B1 × 1 0 - 4
  3. C1 × 1 0 - 6
  4. D1 0 - 5

Correct answer

A. 1 × 1 0 - 8

Step-by-step solution

K   =   α 2 C 1 − α ;   1 − α ≈ 1 ∴ K = α 2 C = 0 .01 100 2 × 1 = 1 × 1 0 - 8 .

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