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NTA Abhyas NEET2020ChemistryIonic EquilibriumPractice

Equimolar solutions of HF, HCOOH and HCN at 298 K have the values of K a as 6.8 × 1 0 - 4 , 1.8 × 1 0 - 4 and 4.8 × 1 0 - 9 respectively. What will be the order of their acidic strength?

Options

  1. AHF > HCN > HCOOH
  2. BHF > HCOOH > HCN
  3. CHCN > HF > HCOOH
  4. DHCOOH > HCN > HF

Correct answer

B. HF > HCOOH > HCN

Step-by-step solution

Solution which has higher Ka value will have more acidic strength . So, K a H F 6.8 × 1 0 - 4 > H C O O H 1.8 × 1 0 - 4 > H C N 4.8 × 1 0 - 9

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