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NTA Abhyas NEET2020ChemistryIonic EquilibriumPractice

M ( O H ) x has a K s p or 4 × 1 0 - 9 and its is solubility is 1 0 - 3 M. The value of x is

Options

  1. A4
  2. B1
  3. C3
  4. D2

Correct answer

D. 2

Step-by-step solution

M(OH) x ⇌ M 10 − 3 x+ + xOH − x×10 − 3 K sp = [M x+ ] × [OH − ] x 4   ×   10 − 9   =   ( 10 − 3 )   ×   (x   ×   10 − 3 ) x On solving x   =   2

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