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NTA Abhyas NEET2020ChemistryIonic EquilibriumPractice

The solubility in terms of K s p for A 3 B ( a q ) is

Options

  1. AK s p 3 1 / 4
  2. BK s p 27 1 / 4
  3. C( 27 K s p ) 1 / 4
  4. D( 3 K s p ) 1 / 4

Correct answer

B. K s p 27 1 / 4

Step-by-step solution

A 3 B(aq) ⇌ 3A + 3s + B 3 − s K s p = 27 s 3 × s = 27 s 4 s = K s p 27 1 / 4

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