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NTA Abhyas NEET2020ChemistryIonic EquilibriumPractice

Calculate the pH of buffer solution prepared by dissolving 0.20 mol of sodium cyanate (NaCNO) and 1.0 mol of cynic acid (HCNO) in enough water to make 1.0 litre of slution. K a ( H C N O ) = 2.0 × 1 0 - 4 .

Options

  1. A0
  2. B3.0
  3. C4.4
  4. D5.0

Correct answer

B. 3.0

Step-by-step solution

pH = - l o g K a ( H C N O ) + l o g [ N a C N O ] [ H C N O ] = − log ( 2.0 × 10 − 4 ) + log 0.20   mol/L 1.0   mol/L = 3.7 + ( - 0.67 ) = 3.03 ≃ 3.0

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