Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas NEET2020ChemistryIonic EquilibriumPractice

K 1 and K 2 for oxalic acid are 6.5 × 1 0 2 - and 6.1 × 1 0 - 5 respectively. What will be [ H O - ] in a 0.01 M solution of sodium oxalate?

Options

  1. A9.6 × 1 0 - 6
  2. B1.4 × 1 0 - 1
  3. C1.28 × 1 0 - 6
  4. D1.3 × 1 0 - 8

Correct answer

C. 1.28 × 1 0 - 6

Step-by-step solution

The hydrolysis of C 2 O 4 2 - is represented by C 2 O 4 2 - + H 2 O ⇌ H C 2 O 4 - + O H - K h = K w K 2 = 1.0 × 1 0 - 14 6.1 × 1 0 - 5 = x 2 0.01 So x = 1.28 × 1 0 - 6

Practice Ionic Equilibrium on Quantrex Academy →

More from Ionic Equilibrium

What amount of NaOH should be dissolved in a 500 mL solution, so that the p ^ H of solution is 12 at 298 K ? 2026Which of the following buffer solutions is used for precipitation of cations of the III A group? 2026The degree of dissociation of weak acid is directly proportional to 2026Which from the following is Lewis base? 2026The solubility of Fe(OH) ₃ is x mole per liter. Find its K_ sp . 2026The Basic buffer solution is made with 0.1 M NH ₄ OH and 0.2 M NH ₄ Cl . If K_b for the base is 1.8 10⁻⁵ , what is the pH of the buffer? 2026The hydrogen ion concentration of the ocean is about 2 10⁻⁹ M . What is the pOH of ocean? 2026Calculate the dissociation constant of a weak monobasic acid if it is 0.04% dissociated in a 0.01M solution. 2026 Full Ionic Equilibrium list All NTA Abhyas NEET PYQs