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BITSAT Complex Number PYQs with Solutions

30 previous year questions from Complex Number (BITSAT Mathematics) with answers and solutions. Numbered list, year tags, and one-tap solutions — built for serious JEE / NEET practice.

30 questionsMathematics2009–2024Answers + solutions

About Complex Number PYQs

Complex Number has 30 previous year questions in the Quantrex Academy BITSAT Mathematics bank. The 30 questions in this list come from BITSAT (30), spanning 2009 to 2024. Each question opens on its own page with the options, the correct answer and the worked solution where available.

Questions by year (this list)

  • 2024: 5
  • 2023: 2
  • 2022: 2
  • 2021: 2
  • 2020: 1
  • 2019: 2
  • 2018: 1
  • 2017: 2
  • 2016: 1
  • 2015: 2
  • 2014: 3
  • 2013: 2

Complex Number questions with solutions

1

The points represented by the complex number 1+i,-2+3 i, (5)/(3) i on the argand plane are

BITSAT 2024 Solution
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2

The modulus of the complex number z such that |z+3-i|=1 and (z)=π is equal to

BITSAT 2024 Solution
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3

If z, z ,-z,- z forms a rectangle of area 2 3 square units, then one such z is

BITSAT 2024 Solution
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4

If z_1, z_2, … . . z_n are complex numbers such that |z_1|=|z_2|=… . .=|z_n|=1 , then |z_1+z_2+… . .+z_n| is equal to

BITSAT 2024 Solution
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5

If |z_1|=2,|z_2|=3,|z_3|=4 and |2 z_1+3 z_2+4 z_3|= 4 , then absolute value of 8 z_2 z_3+27 z_3 z_1+64 z_1 z_2 equals

BITSAT 2024 Solution
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6

The modulus of (1+i 3 )(2+2 i) ( 3 -i) is

BITSAT 2023 Solution
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7

i^ 57 + 1 i^ 25 , when simplified has the value

BITSAT 2023 Solution
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8

If |w|=2 , then the set of points z=w-(1)/(w) is contained in or equal to the set of points z satisfying

BITSAT 2022 Solution
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9

The smallest positive integral value of n such that [(1+ (π)/(8)+i (π)/(8))/(1+ (π)/(8)-i (π)/(8))]^n is purely imaginary, is equal to

BITSAT 2022 Solution
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10

If z is a complex number such that z^ 2 =( z )^ 2 , then

BITSAT 2021 Solution
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11

If z_ 1 = 2 [ (π)/(4)+i (π)/(4)] and z_ 2 = 3 [ (π)/(3)+ i (π)/(3)] then | z_ 1 z_ 2 |is equal to m . Value of m is

BITSAT 2021 Solution
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12

If |z_ 1 |=|z_ 2 |=… … … . .|z_ n |=1, then the value of |z_ 1 +z_ 2 +… … . z_ n |-| 1 z_ 1 + 1 z_ 2 +… … .+ 1 z_ n | is,

BITSAT 2020 Solution
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13

The value of λ for which the loci argz = (π)/(6) and | z - 2 3 i | = λ on the argand plane touch each other is&

BITSAT 2019 Solution
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14

If z _ 1 and ¯ z 1 represents adjacent vertices of a regular polygon of n sides and if Im( z _ 1 ) Re( z _ 1 ) = 2 - 1 , then n is equal to

BITSAT 2019 Solution
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15

The n^ th roots of unity are in

BITSAT 2018 Solution
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16

If z = a + ib satisfies arg ( z - 1 ) = arg ( z + 3i ) , then ( a - 1 ) : b =

BITSAT 2017 Solution
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17

If z _ 1 , z _ 2 and z _ 3 represent the vertices of an equilateral triangle such that | z _ 1 | = | z _ 2 | = | z _ 3 | then

BITSAT 2017 Solution
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18

If z_ 1 = 3 +i 3 and z_ 2 = 3 +i , then the complex number ( z_ 1 z_ 2 )^ 50 lies in the :

BITSAT 2016 Solution
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19

The root of the equation 2(1+i) x^ 2 -4(2-i) x-5-3 i=0 which has greater modulus is

BITSAT 2015 Solution
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20

If complex number z_ 1 , z_ 2 and 0 are vertices of equilateral triangle, then z_ 1 ^ 2 +z_ 2 ^ 2 -z_ 1 z_ 2 is equal to

BITSAT 2015 Solution
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21

If z=x+i y, z^ 1 / 3 =a-i b, then (x)/(a)-(y)/(b)=k (a^ 2 -b^ 2 ) where k is equal to

BITSAT 2014 Solution
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22

i^ 57 + 1 i^ 25 , when simplified has the value

BITSAT 2014 Solution
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23

The complex number z=z+i y which satisfies the equation |(z-3 i)/(z+3 i)|=1, lies on

BITSAT 2014 Solution
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24

If the real part of z +2 z -1 is 4, z ≠ 1, then the locus of the point representing z in the complex plane is

BITSAT 2013 Solution
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25

If α and β are the roots of x^ 2 -x+1=0, then the equation whose roots are α^ 100 and β^ 100 are

BITSAT 2013 Solution
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26

The amplitude of (π)/(5)+i (1- (π)/(5))

BITSAT 2012 Solution
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27

If x=ω-ω^ 2 -2, then the value of x^ 4 +3 x^ 3 +2 x^ 2 -11 x-6 is

BITSAT 2012 Solution
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28

If \(a > 0, a ∈ ℝ, z=a+2 i\) and \(z|z|-a z+1=0\) then

BITSAT 2011 Solution
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29

The roots of the equation \(x²-2 2 x+1=0\) are

BITSAT 2010 Solution
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30

For the equation \( (1)/(x+a)-(1)/(x+b)=(1)/(x+c) \), if the product of roots is zero, then the sum of roots is

BITSAT 2009 Solution
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