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BITSAT Sequences and Series PYQs with Solutions

51 previous year questions from Sequences and Series (BITSAT Mathematics) with answers and solutions. Numbered list, year tags, and one-tap solutions — built for serious JEE / NEET practice.

51 questionsMathematics2009–2024Answers + solutions

About Sequences and Series PYQs

Sequences and Series has 51 previous year questions in the Quantrex Academy BITSAT Mathematics bank. The 51 questions in this list come from BITSAT (51), spanning 2009 to 2024. Each question opens on its own page with the options, the correct answer and the worked solution where available.

Questions by year (this list)

  • 2024: 8
  • 2023: 2
  • 2022: 4
  • 2021: 4
  • 2020: 7
  • 2018: 2
  • 2017: 2
  • 2016: 5
  • 2015: 3
  • 2014: 3
  • 2013: 1
  • 2012: 2

Sequences and Series questions with solutions

1

If a>0, b>0, c>0 and a, b, c are distinct, then (a+b)(b+c)(c+a) is greater than

BITSAT 2024 Solution
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2

If ∑_ k=1 ^n k(k+1)(k-1)=p n^4+q n^3+t n^2+s n where p, q, t and s are constants, then the value of s is equal to

BITSAT 2024 Solution
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3

There are four numbers of which the first three are in GP and the last three are in AP, whose common difference is 6. If the first and the last numbers are equal, then two other

BITSAT 2024 Solution
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4

If A=1+r^a+r^ 2 a +r^ 3 a +… ∞ and B=1+ ^ b + ^ 2 b + ^ 3 b +… ∞ , then a b is equal to

BITSAT 2024 Solution
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5

The sum of the infinite series 1+(5)/(6)+(12)/(6^2)+(22)/(6^3)+(35)/(6^4)+(51)/(6^5)+(70)/(6^6)+…. . is equal to:

BITSAT 2024 Solution
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6

If ^ -1 [(1)/(1+1.2)]+ ^ -1 [(1)/(1+2.3)]+…+ ^ -1 [(1)/(1+n(n+1))]= ^ -1 [x] , then x is equal to

BITSAT 2024 Solution
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7

If arithmetic mean of two distinct positive real number a and b(a > b) be twice their geometric mean, then a: b=

BITSAT 2024 Solution
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8

If y= ^ -1 (1)/(x^2+x+1)+ ^ -1 (1)/(x^2+3 x+3)+ ^ -1 (1)/(x^2+5 x+7)+… .to n terms, then (d y)/(d x)=

BITSAT 2024 Solution
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9

The sum to infinite term of the series 1+(2)/(3)+(6)/(3^2)+(10)/(3^3)+(14)/(3^4)+⋯ is

BITSAT 2023 Solution
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10

If the sum of an infinite GP a, a r, a r^2, a r^3, … is 15 and the sum of the squares of its each term is 150 , then the sum of a r^2, a r^4, a r^6, … is :

BITSAT 2023 Solution
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11

Let a_1, a_2, … … a_ 40 be in AP and h_1, h_2, …. h_ 10 be in HP. If a_1=h_1=2 and a_ 10 =h_ 10 =3 , then a_4 h_7 is

BITSAT 2022 Solution
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12

Let a_1, a_2, a_3 … be a harmonic progression with a_1=5 and a_ 20 =25 . The least positive integer n for which a_n < 0 , is

BITSAT 2022 Solution
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13

In a sequence of 21 terms, the first 11 terms are in AP with common difference 2 and the last 11 terms are in GP with common ratio 2 . If the middle term of AP be equal to the

BITSAT 2022 Solution
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14

If α, β, γ ∈[0, π] and if α, β, γ are in AP, then ( α- γ)/( γ- α) is equal to

BITSAT 2022 Solution
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15

If the sum of a certain number of terms of the A.P. 25,22,19, … is 116 then the last term is

BITSAT 2021 Solution
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16

The sum of all odd numbers between 1 and 1000 which are divisible by 3 is

BITSAT 2021 Solution
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17

Consider an infinite geometric series with first term a and common ratio r . If its sum is 4 and the second term is (3)/(4) , then:

BITSAT 2021 Solution
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18

If the harmonic mean between a and b be H , then the value of 1 H-a + 1 H-b is

BITSAT 2021 Solution
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19

If a, b, c are positive numbers, then least value of (a+b+c) ((1)/(a)+(1)/(b)+(1)/(c))is

BITSAT 2020 Solution
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20

The sum of the infinite series 2^ 2 2 ! + 2^ 4 4 ! + 2^ 6 6 ! +… is equal to

BITSAT 2020 Solution
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21

A student read common difference of an A. P. as -2 instead of 2 and got the sum of first 5 terms as -5. Actual sum of first five terms is

BITSAT 2020 Solution
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22

If a > 0, b > 0, c > 0 and a, b, c are distinct, then (a+ b) (b+c)(c+a) is greater than

BITSAT 2020 Solution
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23

If y=3 x+6 x^ 2 +10 x^ 3 +… … …, ∞, then (1)/(3) y- 1.4 3^ 2 2 y^ 2 + 1.4.7 3^ 2 3 y^ 3 -… … ∞ is equal to

BITSAT 2020 Solution
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24

If a, c, b are in G.P., then the area of the triangle formed by the lines a x+b y+c=0 with the coordinates axes is equal to

BITSAT 2020 Solution
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25

There are four numbers of which the first three are in G.P. and the last three are in A.P., whose common difference is 6. If the first and the last numbers are equal then two

BITSAT 2020 Solution
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26

If a, b, c are in GP and loga - log2b, log2b - log3c and log3c - loga are in AP , then a, b and c are the lengths of the sides of a triangle, which is

BITSAT 2018 Solution
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27

If ∑ _ r = 1 ^ n t _ r = (n(n + 1)(n + 2)(n + 3))/(8), where t _ r denotes the r ^ th term of a series, then _ n → ∞ ∑ _ r = 1 ^ n 1 t _ r is

BITSAT 2018 Solution
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28

The numbers 3 ^ 2sin2α - 1 , 14 and 3 ^ 4 - 2sin2α form first three terms of an A. P. ,& then its fifth term is

BITSAT 2017 Solution
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29

If cos ( x - y ) , cosx and cos ( x + y ) are in HP , then cosxsec ( y / 2 ) is equal to

BITSAT 2017 Solution
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30

The arithmetic mean of numbers a, b, c, d, e is M . What is the value of (a-M)+(b-M)+(c-M)+(d-M)+(e-M) ?

BITSAT 2016 Solution
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31

The fourth term of an A.P. is three times of the first term and the seventh term exceeds the twice of the third term by one, then the common difference of the progression is

BITSAT 2016 Solution
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32

The sum to n terms of the series (1)/(2)+(3)/(4)+(7)/(8)+(15)/(16)+… … … … is

BITSAT 2016 Solution
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33

If a, b , and c are in A.P. and also a - 2 b, 2 b- 3 c, 3 c- a are in A.P., then

BITSAT 2016 Solution
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34

(x+(1)/(x))^ 2 +(x^ 2 + 1 x^ 2 )^ 2 +(x^ 3 + 1 x^ 3 )^ 2 … . upto n terms is

BITSAT 2016 Solution
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35

If ω is the complex cube root of unity, then the value of ω+ω^ ((1)/(2)+(3)/(8)+(9)/(32)+(27)/(128)+…) is

BITSAT 2015 Solution
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36

The value of (3)/(4)+(15)/(16)+(63)/(64)+… upto n terms is

BITSAT 2015 Solution
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37

If binomial coefficients of three consecutive terms of (1+x)^ 2 are in H P , then the maximum value of n is

BITSAT 2015 Solution
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38

If the (2 p)^ th term of a H . P . is q and the (2 q)^ th term is p, then the 2(p+q)^ th term is-

BITSAT 2014 Solution
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39

If 1 a , 1 ~b , 1 c are in A. P., then ( 1 a + 1 ~b - 1 c ) ((1)/(b)+(1)/(c)-(1)/(a)) is equal to

BITSAT 2014 Solution
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40

The product of n positive numbers is unity, then their sum is:

BITSAT 2014 Solution
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41

The sum of the series 1+2.2+3.2^ 2 +4.2^ 3 +….+100.2^ 99 is

BITSAT 2013 Solution
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42

If x is positive then the sum to infinity of the series (1)/(1+3 x)- 1-3 x (1+3 x)^ 2 + (1-3 x)^ 2 (1+3 x)^ 3 - (1-3 x)^ 3 (1+3 x)^ 4 … ∞ is

BITSAT 2012 Solution
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43

Let a_ 1 , a_ 2 , a_ 3 … … … …. be terms on A.P. If a_ 1 +a_ 2 +… … … a_ p a_ 1 +a_ 2 +… … ….+a_ q = p^ 2 q^ 2 , p ≠ q, then a_ 6 a_ 21 equals

BITSAT 2012 Solution
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44

If \( ^ th , ^ th \) and \( ^ th \) terms of H.P. are \( u, v, w respectively, then find the value of the expression \((q-r) v w+(r-p) w u+(p-q) u v\).

BITSAT 2011 Solution
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45

If the sum of the first \(2 n\) terms of \(2,5,8, … …\) is equal to the sum of the first \(n\) terms of 57,59 , \(61 … …\). , then \( n \) is equal to

BITSAT 2011 Solution
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46

Find the A.M. of the first ten odd numbers.

BITSAT 2011 Solution
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47

The coefficient of \(x^ 32 \) in the expansion of \( (x^4-(1)/(x^3) )^ 15 is:

BITSAT 2010 Solution
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48

A wholesale merchant wants to start the business of cereal with \(₹ 24000\). Wheat is \(₹ 400\) per quintal and rice is \(₹ 600\) per quintal. He has capacity to store 200 quintal

BITSAT 2010 Solution
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49

If in the expansion of \( ( 2^x+ (1)/(4^x))^ n, T_3=7 T_2\) and sum of the binomial coefficients of second and third terms is 36 , then the value of \(x\) is -

BITSAT 2009 Solution
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50

If \(A\) and \(B\) are \(2 × 2\) matrices, then which of the following is true?

BITSAT 2009 Solution
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51

The minimum value of the function \(z=4 x+3 y\) subject to the constraints \(3 x+2 y ≥ 160,5 x+2 y ≥ 200\), \(x+2 y ≥ 80, x ≥ 0, y ≥ 0\) is

BITSAT 2009 Solution
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