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NEET
Exam
NEET
Subject
Physics
Chapter
Mathematics in Physics

NEET · Physics · Mathematics in Physics

In an experiment, the percentage errors in the measurement of three...

In an experiment, the percentage errors in the measurement of three physical quantities AA, BB, and CC are 1%1\%, 2%2\%, and 4%4\% respectively. Match the derived quantities in List-I with their maximum percentage errors in List-II.

List-IList-II
(P) X=A⋅B2CX = \dfrac{A \cdot B^2}{\sqrt{C}}(1) 8%8\%
(Q) Y=A2⋅BCY = \dfrac{A^2 \cdot B}{C}(2) 7%7\%
(R) Z=A⋅B3CZ = \dfrac{\sqrt{A} \cdot B^3}{C}(3) 9%9\%
(S) W=A3B⋅CW = \dfrac{A^3}{B \cdot C}(4) 10.5%10.5\%

Choose the correct answer from the options given below:

Options

  1. A(P)-(1), (Q)-(2), (R)-(4), (S)-(3)
  2. B(P)-(2), (Q)-(4), (R)-(1), (S)-(3)
  3. C(P)-(2), (Q)-(1), (R)-(4), (S)-(3)
  4. D(P)-(3), (Q)-(1), (R)-(4), (S)-(2)

Correct answer

C. (P)-(2), (Q)-(1), (R)-(4), (S)-(3)

Step-by-step solution

The maximum percentage error for a quantity Q=AaBbCcQ = \dfrac{A^a B^b}{C^c} is given by ΔQQ×100=a(ΔAA×100)+b(ΔBB×100)+c(ΔCC×100)\dfrac{\Delta Q}{Q} \times 100 = a\left(\dfrac{\Delta A}{A} \times 100\right) + b\left(\dfrac{\Delta B}{B} \times 100\right) + c\left(\dfrac{\Delta C}{C} \times 100\right).

For (P): X=A⋅B2C1/2X = \dfrac{A \cdot B^2}{C^{1/2}}
%X=1%+2(2%)+12(4%)=1%+4%+2%=7%\%X = 1\% + 2(2\%) + \dfrac{1}{2}(4\%) = 1\% + 4\% + 2\% = 7\%. (Matches 2)

For (Q): Y=A2⋅BCY = \dfrac{A^2 \cdot B}{C}
%Y=2(1%)+2%+4%=2%+2%+4%=8%\%Y = 2(1\%) + 2\% + 4\% = 2\% + 2\% + 4\% = 8\%. (Matches 1)

For (R): Z=A1/2⋅B3CZ = \dfrac{A^{1/2} \cdot B^3}{C}
%Z=12(1%)+3(2%)+4%=0.5%+6%+4%=10.5%\%Z = \dfrac{1}{2}(1\%) + 3(2\%) + 4\% = 0.5\% + 6\% + 4\% = 10.5\%. (Matches 4)

For (S): W=A3B⋅CW = \dfrac{A^3}{B \cdot C}
%W=3(1%)+2%+4%=3%+2%+4%=9%\%W = 3(1\%) + 2\% + 4\% = 3\% + 2\% + 4\% = 9\%. (Matches 3)

Therefore, the correct matching is (P)-(2), (Q)-(1), (R)-(4), (S)-(3).

Answer: (P)-(2), (Q)-(1), (R)-(4), (S)-(3)
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