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The heat dissipated in a resistance wire is given by Joule's law of heating, H = I^2 R t . In an experiment, the maximum percentage errors in the measurement of heat dissipated ( H ), resistance ( R ), and time ( t ) are 9 % , 2 % , and 1 % respectively. The percentage error in the measurement of current ( I ) is:

Options

  1. A6 %
  2. B12 %
  3. C3 %
  4. D4.5 %

Correct answer

C. 3 %

Step-by-step solution

The formula for heat dissipated is H = I^2 R t . The maximum percentage error in H is given by the sum of the percentage errors of its factors, multiplied by their respective powers: H H 100 = 2 ( I I 100 ) + ( R R 100 ) + ( t t 100 ) Given the percentage errors: H H 100 = 9 % R R 100 = 2 % t t 100 = 1 % Substitute these values into the error equation: 9 % = 2 ( I I 100 ) + 2 % + 1 % 9 % = 2 ( I I 100 ) + 3 % 2 ( I I 100 ) = 9 % - 3 % = 6 % I I 100 = 6 % 2 = 3 % The percentage error in the measurement of current is

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