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AIIMS 201925 May
Exam
AIIMS
Year
2019
Date
25 May
Subject
Physics
Chapter
Mathematics in Physics

AIIMS 2019 · 25 May · Physics · Mathematics in Physics

A potential difference V=100 ± 5 ~V , when applied across a...

A potential difference V=100±5 VV=100 \pm 5 \mathrm{~V}, when applied across a resistance, gives a current I=10±0.2 AI=10 \pm 0.2 \mathrm{~A}. What is the percentage error in RR ?

Options

  1. A2%2 \%
  2. B5%5 \%
  3. C7%7 \%
  4. D8%8 \%

Correct answer

C. 7%7 \%

Step-by-step solution

Potential difference is V=100±5 VV=100 \pm 5 \mathrm{~V} Current is I=10±0.2 AI=10 \pm 0.2 \mathrm{~A}. Percentage error in voltage is obtained as ΔVV=5100×100%=5%\frac{\Delta V}{V}=\frac{5}{100} \times 100 \%=5 \% Percentage error in current is obtained as ΔII=0.210×100%=2%\frac{\Delta I}{I}=\frac{0.2}{10} \times 100 \%=2 \% Using, R=VIR=\frac{V}{I}, the percentage error in resistance is calculated as R=5%+2%=7%R=5 \%+2 \%=7 \%.
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