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NEET
Exam
NEET
Subject
Physics
Chapter
Units and Dimensions

NEET · Physics · Units and Dimensions

If Planck's constant (h) , speed of light in vacuum (c) and...

If Planck's constant (h)(h), speed of light in vacuum (c)(c) and Newton's gravitational constant (G)(G) are taken as fundamental quantities, which of the following physical quantities has the dimensional formula [h1/2c−5/2G1/2][h^{1/2} c^{-5/2} G^{1/2}]?

Options

  1. AMass
  2. BTime
  3. CLength
  4. DEnergy

Correct answer

B. Time

Step-by-step solution

The standard dimensional formulas of the given constants are:
Planck's constant, h=[ML2T−1]h = [ML^2T^{-1}]
Speed of light, c=[LT−1]c = [LT^{-1}]
Gravitational constant, G=[M−1L3T−2]G = [M^{-1}L^3T^{-2}]

Let us evaluate the dimensions of the given expression [h1/2c−5/2G1/2][h^{1/2} c^{-5/2} G^{1/2}]:
First, find the product hGhG:
hG=[ML2T−1]×[M−1L3T−2]=[L5T−3]hG = [ML^2T^{-1}] \times [M^{-1}L^3T^{-2}] = [L^5T^{-3}]

Now, raise it to the power of 1/21/2:
(hG)1/2=[L5/2T−3/2](hG)^{1/2} = [L^{5/2}T^{-3/2}]

Next, evaluate c−5/2c^{-5/2}:
c−5/2=[LT−1]−5/2=[L−5/2T5/2]c^{-5/2} = [LT^{-1}]^{-5/2} = [L^{-5/2}T^{5/2}]

Multiplying these terms together:
[h1/2c−5/2G1/2]=[L5/2T−3/2]×[L−5/2T5/2][h^{1/2} c^{-5/2} G^{1/2}] = [L^{5/2}T^{-3/2}] \times [L^{-5/2}T^{5/2}]
=[L5/2−5/2T−3/2+5/2]= [L^{5/2 - 5/2} T^{-3/2 + 5/2}]
=[L0T1]=[T]= [L^0 T^1] = [T]

This is the dimensional formula of time.

Answer: Time
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